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C program to count total number of negative elements in array

C program to count total number of negative elements in array

Write a C program to read elements in an array and count total number of negative elements in array. C program to find all negative elements in an array.

Logic to count total negative/positive elements in an array

    Input size and array elements from user. Store it in some variable say n and array.
    To store count of negative elements, declare and initialize a variable with 0, say count = 0.
    Run a loop from 0 to n i.e. size of array. The loop structure should look like for(j=0; j<n; j++).
    Inside the loop check if the current number is negative, then increment the count by 1. Means perform if(array[j] < 0) then, count = count + 1.
    Finally, after loop you are left with total negative element count.

#include <stdio.h>

int main()
{
    int array[88]; //Declares an array of size 88
    int j, n, count=0;

    /* Input size of the array */
    printf("Enter size of the array : ");
    scanf("%d", &n);


    /* Input array elements */
    printf("Enter elements in array : ");
    for(j=0; j<n; j++)
    {
        scanf("%d", &array[j]);
    }

    /*
     * Counts total number of negative elements in array
     */
    for(j=0; j<n; j++)
    {
        /* Increment count if current array element is negative */
        if(array[j]<0)
        {
            count++;
        }
    }

    printf("\nTotal number of negative elements = %d", count);

    return 0;
}