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Program to Find the two Elements such that their Sum is Closest to Zero

Program to Find the two Elements such that their Sum is Closest to Zero

- Initialize the array named array[] with the random values.
- Call the function minabsvaluepair and pass array and its size as parameters.
- In the function definition receive the parameters through variables array[] and array_size.
- If the array_size is less than 2, then print the output as "Invalid Input" and exit.
- Initialize the variables min_l and min_r with 0 and 1 respectively.
- Initialize the variable min_sum with the sum of 1st two elements of the array.
- Using two for loops, compare all the combinations with this default sum.
- If the minimum one exits, then change the values of variables min_l and min_r with this new array positions and exit.
- Print the array values with the positions min_l and min_r as output and exit.

    # include <stdio.h>

    # include <stdlib.h>

    # include <math.h>

    void minabsvaluepair(int array[], int array_size)

    {

        int count = 0;

        int l, r, min_sum, sum, min_l, min_r;

        /* Array should have at least two elements*/

        if (array_size < 2)

        {

            printf("Invalid Input");

            return;

        }

        /* Initialization of values */

        min_l = 0;

        min_r = 1;

        min_sum = array[0] + array[1];

        for (l = 0; l < array_size - 1; l++)

        {

            for (r = l + 1; r < array_size; r++)

            {

                sum = array[l] + array[r];

                if (abs(min_sum) > abs(sum))

                {

                    min_sum = sum;

                    min_l = l;

                    min_r = r;

                }

            }

        }

        printf(" The two elements whose sum is minimum are %d and %d", array[min_l], array[min_r]);

    }

    int main()

    {

        int array[] = {13, 18, -29, 36, -16, 38};

        minabsvaluepair(array, 6);

        getchar();

        return 0;

    }