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C Programming - C Logical Operators



C Programming - C Logical Operators

An expression containing logical operator returns either 0 or 1 depending upon whether expression results true or false.

Operator 	Meaning of Operator                     	                        Example
&& 	        Logial AND. True only if all operands are true        	If z = 8 and d = 2 then, expression ((z == 8) && (d > 8)) equals to 0.
|| 	        Logical OR. True only if either one operand is true 	If z = 8 and d = 2 then, expression ((z == 8) || (d > 8)) equals to 1.
! 	        Logical NOT. True only if the operand is 0             	If z = 8 then, expression ! (z == 8) equals to 0.


// C Program to demonstrate the working of logical operators

#include <stdio.h>
int main()
{
    int x = 8, y = 8, z = 10, result;

    result = (x == y) && (z > y);
    printf("(x == y) && (z > y) equals to %d \n", result);

    result = (x == y) && (z < y);
    printf("(x == y) && (z < y) equals to %d \n", result);

    result = (x == y) || (z < y);
    printf("(x == y) || (z < y) equals to %d \n", result);

    result = (x != y) || (z < y);
    printf("(x != y) || (z < y) equals to %d \n", result);

    result = !(x != y);
    printf("!(x == y) equals to %d \n", result);

    result = !(x == y);
    printf("!(x == y) equals to %d \n", result);

    return 0;

}

Explanation of logical operator program

    (x == y) && (z > 8) evaluates to 1 because both operands (x == y) and (z > y) is 1 (true).
    (x == y) && (z < y) evaluates to 0 because operand (z < y) is 0 (false).
    (x == y) || (z < y) evaluates to 1 because (x = y) is 1 (true).
    (x != y) || (z < y) evaluates to 0 because both operand (x != y) and (z < y) are 0 (false).
    !(x != y) evaluates to 1 because operand (x != y) is 0 (false). Hence, !(x != y) is 1 (true).
    !(x == y) evaluates to 0 because (x == y) is 1 (true). Hence, !(x == y) is 0 (false).