C Programming Code Examples

C > Conversions Code Examples

C Program to Convert Hexadecimal to Binary



C Program to Convert Hexadecimal to Binary

This program takes a hexadecimal number and converts to binary number.

Take a hexadecimal number as input.
For each bit of a hexadecimal number print its equivalent binary number in a four bit fashion. Example: For 22 print it as 0010 0010.
Use switch statement to access each bit of a hexadecimal number.


    #include <stdio.h>

    #define MAX 1000
     

    int main()

    {

        char binarynumber[MAX], hexa[MAX];

        long int i = 0;
    

        printf("Enter the value for hexadecimal ");

        scanf("%s", hexa);

        printf("\n Equivalent binary value: ");

        while (hexa[i])

        {

            switch (hexa[i])

            {

            case '0':

                printf("0000"); break;

            case '1':

                printf("0001"); break;

            case '2':

                printf("0010"); break;

            case '3':

                printf("0011"); break;

            case '4':

                printf("0100"); break;

            case '5':

                printf("0101"); break;

            case '6':

                printf("0110"); break;

            case '7':

                printf("0111"); break;

            case '8':

                printf("1000"); break;

            case '9':

                printf("1001"); break;

            case 'A':

                printf("1010"); break;

            case 'B':

                printf("1011"); break;

            case 'C':

                printf("1100"); break;

            case 'D':

                printf("1101"); break;

            case 'E':

                printf("1110"); break;

            case 'F':

                printf("1111"); break;

            case 'a':

                printf("1010"); break;

            case 'b':

                printf("1011"); break;

            case 'c':

                printf("1100"); break;

            case 'd':

                printf("1101"); break;

            case 'e':

                printf("1110"); break;

            case 'f':

                printf("1111"); break;

            default:

                printf("\n Invalid hexa digit %c ", hexa[i]);

                return 0;

            }

            i++;

        }

        return 0;

    }

Take a hexadecimal number as input and store it in the array hexa.
Using switch statement access each bit of the hexadecimal number and print its equivalent binary number in a four bit fashion as shown in the program.
Do step 2 for every bit of a input number. Use while loop to do this.