C Programming Code Examples C > Conversions Code Examples C Program to Convert Hexadecimal to Binary C Program to Convert Hexadecimal to Binary This program takes a hexadecimal number and converts to binary number. Take a hexadecimal number as input. For each bit of a hexadecimal number print its equivalent binary number in a four bit fashion. Example: For 22 print it as 0010 0010. Use switch statement to access each bit of a hexadecimal number. #include <stdio.h> #define MAX 1000 int main() { char binarynumber[MAX], hexa[MAX]; long int i = 0; printf("Enter the value for hexadecimal "); scanf("%s", hexa); printf("\n Equivalent binary value: "); while (hexa[i]) { switch (hexa[i]) { case '0': printf("0000"); break; case '1': printf("0001"); break; case '2': printf("0010"); break; case '3': printf("0011"); break; case '4': printf("0100"); break; case '5': printf("0101"); break; case '6': printf("0110"); break; case '7': printf("0111"); break; case '8': printf("1000"); break; case '9': printf("1001"); break; case 'A': printf("1010"); break; case 'B': printf("1011"); break; case 'C': printf("1100"); break; case 'D': printf("1101"); break; case 'E': printf("1110"); break; case 'F': printf("1111"); break; case 'a': printf("1010"); break; case 'b': printf("1011"); break; case 'c': printf("1100"); break; case 'd': printf("1101"); break; case 'e': printf("1110"); break; case 'f': printf("1111"); break; default: printf("\n Invalid hexa digit %c ", hexa[i]); return 0; } i++; } return 0; } Take a hexadecimal number as input and store it in the array hexa. Using switch statement access each bit of the hexadecimal number and print its equivalent binary number in a four bit fashion as shown in the program. Do step 2 for every bit of a input number. Use while loop to do this.
