C Programming Code Examples
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C program to check whether a number is armstrong number or not
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/* C program to check whether a number is armstrong number or not
Write a C program to input a number from user and check whether given number is Armstrong number or not. How to check Armstrong numbers in C program.
What is Armstrong number?
An Armstrong number is a n-digit number that is equal to the sum of the nth power of its digits. For example -
6 = 6^1 = 6
371 = 3^3 + 7^3 + 1^3 = 371
Input a number from user. Store it in some variable say j. Make a temporary copy of the value to some another variable for calculation purposes, say originalNum = j.
Count total digits in the given number, store result in a variable say digits.
Initialize another variable to store the sum of power of its digits ,say sum = 0.
Run a loop till j > 0. The loop structure should look like while(j > 0).
Inside the loop, find last digit of j. Store it in a variable say lastDigit = j % 10.
Now comes the real calculation to find sum of power of digits. Perform sum = sum + pow(lastDigit, digits).
Since the last digit of j is processed. Hence, remove last digit by performing j = j / 10.
After loop check if(originalNum == sum), then it is Armstrong number otherwise not.
C program to check Armstrong number */
#include <stdio.h>
#include <math.h>
int main()
{
int originalNum, j, lastDigit, digits, sum;
/* Input number from user */
printf("Enter any number to check Armstrong number: ");
scanf("%d", &j);
sum = 0;
/* Copy the value of j for processing */
originalNum = j;
/* Find total digits in j */
digits = (int) log10(j) + 1;
/* Calculate sum of power of digits */
while(j > 0)
{
/* Extract the last digit */
lastDigit = j % 10;
/* Compute sum of power of last digit */
sum = sum + round(pow(lastDigit, digits));
/* Remove the last digit */
j = j / 10;
}
/* Check for Armstrong number */
if(originalNum == sum)
{
printf("%d is ARMSTRONG NUMBER", originalNum);
}
else
{
printf("%d is NOT ARMSTRONG NUMBER", originalNum);
}
return 0;
}
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