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Program to display odd numbers without using if statement

Program to display odd numbers without using if statement

Logic to print odd numbers from 1 to n without if statement

The above approach is not optimal approach to print odd numbers. Observe the above program for a while. You will notice that, I am unnecessarily iterating for even numbers, which is not our goal.

    Input upper limit to print odd number from user. Store it in some variable say N.
    Run a loop from 1 to N, increment it by 2 for each iteration. The loop structure should look like for(j=1; j<=N; j+=2).
    Inside the loop body print the value of j.

/* C program to display all odd numbers between 1 to n without using if statement */

#include <stdio.h>

int main()
{
    int j, n;
    
    /* Input upper limit from user */
    printf("Print odd numbers till: ");
    scanf("%d", &n);

    printf("All odd numbers from 1 to %d are: \n", n);

    /* Start a loop from 1, increment it by 2.
         For each repetition prints the number.     */
    for(j=1; j<=n; j+=2)
    {
        printf("%d\n", j);
    }

    return 0;
}

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