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Check Armstrong Number of n digits

Check Armstrong Number of n digits

In case of an Armstrong number of 3 digits, the sum of cubes of each digits is equal to the number itself.

For example: 407 = 4*4*4 + 0*0*0 + 7*7*7  // 407 is an Armstrong number.

#include <stdio.h>
#include <math.h>

int main()
{
    int number, originalNumber, remainder, result = 0, n = 0 ;

    printf("Enter an integer: ");
    scanf("%d", &number);

     originalNumber = number;
    
    while (originalNumber != 0)
    {
        originalNumber /= 10;
        ++n;
    }

    originalNumber = number;

    while (originalNumber != 0)
    {
        remainder = originalNumber%10;
        result += pow(remainder, n);
        originalNumber /= 10;
    }

    if(result == number)
        printf("%d is an Armstrong number.", number);
    else
        printf("%d is not an Armstrong number.", number);

    return 0;
}

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