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C Program to Print Diamond Pattern



C Program to Print Diamond Pattern

- Take the number of rows as input.
- According to the number of rows, print the " " and "*" using for loops.
- Exit.

    #include <stdio.h>

    int main()

    {

        int number, j, k, count = 1;

        printf("Enter number of rows\n");

        scanf("%d", &number);

        count = number - 1;

        for (k = 1; k <= number; k++)

        {

            for (j = 1; j <= count; j++)

                printf(" ");

            count--;

            for (j = 1; j <= 2 * k - 1; j++)

                printf("*");

            printf("\n");

         }

         count = 1;

         for (k = 1; k <= number - 1; k++)

         {

             for (j = 1; j <= count; j++)

                 printf(" ");

             count++;

             for (j = 1 ; j <= 2 *(number - k)-  1; j++)

                 printf("*");

             printf("\n");

          }

          return 0;

    }

- Take the number of rows as input and store in the variable number.
- Firstly decrement the variable number by 1 and assign this value to the variable count.
- Use this variable count as terminator in the for loop to print " ".
- Decrement count by 1.
- Use another for loop starting from 1 to (2*k-1) to print "*".
- Do steps 3, 4, and 5 inside the for loop starting from 1 to variable number.
- Steps 2-6 are used to print half of the diamond pattern.
- For the next half, assign the variable count by 1.
- Use this variable count as terminator in the for loop to print " ".
- Increment count by 1.
- Use another for loop starting from 1 to (2*(number-k)-1) to print "*".
- Do steps 8-11 inside the for loop starting from 1 to value (number-1).