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C Program to Check whether two Strings are Anagrams



C Program to Check whether two Strings are Anagrams

This program takes two strings as input and checks whether two strings are anagrams.

- Take two strings as input and store them in the arrays array1[] and array2[] respectively.
- In the function find_anagram() using while statement sort both the arrays. After sorting compare them using for loop.
- If all the strings are equal then the two strings are anagrams, otherwise they are not anagrams.

    #include <stdio.h>

    int find_anagram(char [], char []);

    int main()

    {

        char array1[100], array2[100];

        int flag;

        printf("Enter the string\n");

        gets(array1);

        printf("Enter another string\n");

        gets(array2);

        flag = find_anagram(array1, array2);

        if (flag == 1)

            printf(""%s" and "%s" are anagrams.\n", array1, array2);

        else

            printf(""%s" and "%s" are not anagrams.\n", array1, array2);

        return 0;

    }

    int find_anagram(char array1[], char array2[])

    {

        int num1[26] = {0}, num2[26] = {0}, j = 0;

     

        while (array1[j] != '\0')

        {

            num1[array1[j] - 'a']++;

            j++;

        }

        j = 0;

        while (array2[j] != '\0')

        {

            num2[array2[j] -'a']++;

            j++;

        }

        for (j = 0; j < 26; j++)

        {

            if (num1[j] != num2[j])

                return 0;

        }

        return 1;

    }