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count number of alphabets, digits and special characters in string using pointers



count number of alphabets, digits and special characters in string using pointers

Write a C program to count total number of alphabets, digits or special characters in a string using loop. How to find total number of alphabets, digits and special characters in a string in C programming.

#include <stdio.h>
#define maxsize 100 // Maximum string size

int main()
{
    char str[maxsize];
    char * s = str;
    int alphabets, digits, others;

    alphabets = digits = others = 0;

    /* Input string from user */
    printf("Enter any string : ");
    gets(str);

    while(*s)
    {
        if((*s >= 'a' && *s <= 'z') || (*s >= 'A' && *s <= 'Z'))
            alphabets++;
        else if(*s>='0' && *s<='9')
            digits++;
        else
            others++;

        s++;
    }

    printf("Alphabets = %d\n", alphabets);
    printf("Digits = %d\n", digits);
    printf("Special characters = %d", others);

    return 0;
}

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